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olgavlk
@olgavlk
July 2022
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Ребят, помогите, пожалуйста, с тригинометрией.
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sedinalana
1
sin(3x-π/4)=1/2
1)3x-π/4=π/6+2πn,n∈z
3x=π/4+π/6+2πn=5π/6+2πn,n∈z
x=5π/18+2πn/3,n∈z
2)3x-π/4=5π/6+2πk,k∈z
3x=π/4+5π/6+2πk=13π/12+2πk,k∈z
x=13π/36+2πk/3,k∈z
2
tg(π-4x)=-1
-tg(-4x)=-1
yg4x=-1
4x=-π/4+πn,n∈z
x=-π/16+πn/4,n∈z
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Answers & Comments
sin(3x-π/4)=1/2
1)3x-π/4=π/6+2πn,n∈z
3x=π/4+π/6+2πn=5π/6+2πn,n∈z
x=5π/18+2πn/3,n∈z
2)3x-π/4=5π/6+2πk,k∈z
3x=π/4+5π/6+2πk=13π/12+2πk,k∈z
x=13π/36+2πk/3,k∈z
2
tg(π-4x)=-1
-tg(-4x)=-1
yg4x=-1
4x=-π/4+πn,n∈z
x=-π/16+πn/4,n∈z