1. M(Fe2O3)=2*56+3*16=160
n=m/M n=80/160=0,5
2. M(FeS)=56+32=88 n=22/88=0,25
3. M(H2SO4)=1*2+32+4*16=98 n=196/98=2
4. M(O2)=2*16=32 n=512/32=16
#5 1. M(NaOH)=16+1+23=40 n(NaOH)=80/40=2 N=2*6,02*10^23=12,04*10^23
2. M(HNO3)=1+14+3*16=63 n=32,5/63=0,52 N=0,52*6.02*10^23=3,13*10^23
3. M(H2SO4)=98 n=1,5 N=1,5*6.02*10^23=9,03*10^23
4. M(O3)=3*16=48 n=3 N=18,06*10^23
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1. M(Fe2O3)=2*56+3*16=160
n=m/M n=80/160=0,5
2. M(FeS)=56+32=88 n=22/88=0,25
3. M(H2SO4)=1*2+32+4*16=98 n=196/98=2
4. M(O2)=2*16=32 n=512/32=16
#5 1. M(NaOH)=16+1+23=40 n(NaOH)=80/40=2 N=2*6,02*10^23=12,04*10^23
2. M(HNO3)=1+14+3*16=63 n=32,5/63=0,52 N=0,52*6.02*10^23=3,13*10^23
3. M(H2SO4)=98 n=1,5 N=1,5*6.02*10^23=9,03*10^23
4. M(O3)=3*16=48 n=3 N=18,06*10^23