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DoctorWho007
@DoctorWho007
March 2022
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Ребят, помогите с первым и вторым заданиями, пожалуйста.
Заранее благодарю.
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manyny06
Verified answer
Решение смотри на фотографии
2 votes
Thanks 1
Марфа200
Sin²β+1/(tg²β+1)=sin²β+ cos²β=1
2*sin510+2√3cos210+tg²240=2*sin150+2√3cos150+tg²120=1*1/2+2√3*(-√3/2)+(-√3)²=1-3+3=1
1 votes
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Решение смотри на фотографии2*sin510+2√3cos210+tg²240=2*sin150+2√3cos150+tg²120=1*1/2+2√3*(-√3/2)+(-√3)²=1-3+3=1