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Vasilya13
@Vasilya13
July 2022
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Ребят помогите срочно!Квадратный трехчлен разложен на множетели,выразите а
4x^2+29x+45=4(x-5)(x-a)
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andrew17nano
4x^2+29x+45=4(X-5)(X-A)
D=11
x1=-5
x2=-2.25
(x+5)(x+2.25)=4(x-5)(x-a)
(x-a)=(x+5)(x+2.25)/4(x+5)=
=a=x(x+2.25)/4
a=x^2+2.25x делаем отдельно x^2+2.25x=1.5
a=1.5
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Answers & Comments
D=11
x1=-5
x2=-2.25
(x+5)(x+2.25)=4(x-5)(x-a)
(x-a)=(x+5)(x+2.25)/4(x+5)=
=a=x(x+2.25)/4
a=x^2+2.25x делаем отдельно x^2+2.25x=1.5
a=1.5