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exampllee1
@exampllee1
July 2022
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Ребят, срочно помогите!!!
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fatt52
Verified answer
График в приложении
===
V=5*4*3=60 м³ p=10^5 Па m=90 кг М=0,029 кг/моль T=?
===
p*V=(m/M)*R*T
T=p*V*M/(m*R)=10^5*60*0.029/(90*8.31)≈233 K
=======================================
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Answers & Comments
Verified answer
График в приложении===
V=5*4*3=60 м³ p=10^5 Па m=90 кг М=0,029 кг/моль T=?
===
p*V=(m/M)*R*T
T=p*V*M/(m*R)=10^5*60*0.029/(90*8.31)≈233 K
=======================================