n(H2)=4.48/22.4=0.2 mol
Mg + 2HCl = MgCl2 + H2
n(H2)=n(Mg) = 0.2 mol
Ar(Mg)=24 a.o.m.
m(Mg)=24 * 0.2 = 4.8 gg
Otvet: 4.8 g
Смотри во вложении)))))
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Answers & Comments
n(H2)=4.48/22.4=0.2 mol
Mg + 2HCl = MgCl2 + H2
n(H2)=n(Mg) = 0.2 mol
Ar(Mg)=24 a.o.m.
m(Mg)=24 * 0.2 = 4.8 gg
Otvet: 4.8 g
Смотри во вложении)))))