morozovsasha04

Ответ:

1) t=arcsin(-√3/2)=-π/6

2)x=arccos(-1/2)=π/3

3)x=arctg(-1)=-π/4

0=1/2*cos(2x+π/3)-1

1=1/2*cos(2x+π/3)

cos(2x+π/3)=2

2x+π/3=arccos(2)+2πn;n€Z

2x=arccos(2)-π/3

x=arccos(2)/2-π/3+2πn;n€Z