Ребятки, помогите пожалуйста!!!. Created by 777ina. algebra-ru

Ребятки, помогите пожалуйста!!!...

Ответ:

$\displaystyle 1) \;\; 2\sqrt[3]{5} =\sqrt[3]{2^{3} *5} =\sqrt[3]{8*5} =\sqrt[3]{40} \\\\2) \;\; b\sqrt[4]{6} = \sqrt[4]{6b^{4} } \; ; \;\;b>0\\\\3) \;\; y\sqrt[4]{2} = -\sqrt[4]{2y^{4} } \; ; \;\;y$

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ldglkva

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Ответ:

Объяснение:

∛( 5*2³)=∛40.

⁴√(6*b⁴),

⁴√2*у⁴.

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