Ребятки , помогите пожалуйста. Created by Nasssaaa. algebra-ru

Ребятки , помогите пожалуйста...

Nasssaaa @Nasssaaa

July 2022 1 4 Report

Ребятки , помогите пожалуйста

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sebrithien

а)

$\displaystyle \tt \frac{x}{8y}\cdot \frac{3y^2}{x}\cdot \frac{4x^2}{y^2}=\frac{1}{2y}\cdot 3x^2=\boxed{\frac{3x^2}{2y}}$

б)

$\displaystyle \tt \frac{x}{3y^2}\div \frac{y}{2x}\cdot \frac{x^2}{y^2}=\frac{x}{3y^2}\cdot \frac{2x}{y}\cdot \frac{x^2}{y^2}=\boxed{\frac{2x^4}{3y^5}}$

в)

$\displaystyle \tt \frac{x}{3y^2}\div (\frac{y}{2x}\cdot \frac{x^2}{y^2})=\frac{x}{3y^2}\div (\frac{1}{2}\cdot \frac{x}{y})=\frac{x}{3y^2}\div \frac{x}{2y}=\frac{x}{3y^2}\div \frac{2y}{x}=\frac{1}{3y}\cdot 2=\boxed{\frac{2}{3y}}$

г)

$\displaystyle \tt \frac{x}{3y^2}\cdot (\frac{y}{2x}\div \frac{x^2}{y^2})=\frac{x}{3y^2}\cdot (\frac{y}{2x}\cdot \frac{y^2}{x^2})=\frac{x}{3y^2}\cdot \frac{y^3}{2x^3}=\frac{1}{3}\cdot \frac{y}{2x^2}=\boxed{\frac{y}{6x^2}}$

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