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Din08
@Din08
August 2022
1
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Ребят,помогите,9 номер,очень срочно
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sedinalana
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Y`=-2√3sin2x-2cos2x+2√3=0
-4√3sinxcosx-2cos²x+2sin²x+2√3sin²x+2√3cos²x=0/cos²x
(2√3+2)tg²x-4√3tgx+(2√3-2)=0
tgx=a
(2√3+2)a²-4√3a+(2√3-2)=0
D=48-4(12-4)=48-32=16
a1=(4√3-4)/(4√3+4)=(√3-1)/(√3+1)=(4-2√3)/(3-1)=2(2-√3)/2=2-√3
a2=(4√3+4)/(4√3+4)=1
+ _ +
---------------(2-√3)----------(1)--------------
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Answers & Comments
Verified answer
Y`=-2√3sin2x-2cos2x+2√3=0-4√3sinxcosx-2cos²x+2sin²x+2√3sin²x+2√3cos²x=0/cos²x
(2√3+2)tg²x-4√3tgx+(2√3-2)=0
tgx=a
(2√3+2)a²-4√3a+(2√3-2)=0
D=48-4(12-4)=48-32=16
a1=(4√3-4)/(4√3+4)=(√3-1)/(√3+1)=(4-2√3)/(3-1)=2(2-√3)/2=2-√3
a2=(4√3+4)/(4√3+4)=1
+ _ +
---------------(2-√3)----------(1)--------------
max min