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анюточкаточка
@анюточкаточка
September 2021
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Решаю методом промежутков не решается(( |3-х-х²|больше или равно |1-2х|
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Verified answer
1-2х>=0 x<=1/2
1-2x<0 x>1/2
3-x-x^2>=0
(-1-√13)/2;(-1+√13)/2
x>=(√13-1)/2<2
x^2+x-3>=2x-1
x^2-x-2>=0
x>=2
x<(-1-√13)/2
x^2+x-3>=1-2x
x^2+3x-4>=0
x<=-4
(1/2;(√13-1)/2)
3-x-x^2>=2x-1
x^2+3x-4<=0
(-4;1)
[1/2;1]
(-1-√13)/2;1/2
3-x-x^2>=1-2x
x^2-x-2<=0
[-1;1/2]
(-∞;-4] U [-1;1] U [2;∞)
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Answers & Comments
Verified answer
1-2х>=0 x<=1/21-2x<0 x>1/2
3-x-x^2>=0
(-1-√13)/2;(-1+√13)/2
x>=(√13-1)/2<2
x^2+x-3>=2x-1
x^2-x-2>=0
x>=2
x<(-1-√13)/2
x^2+x-3>=1-2x
x^2+3x-4>=0
x<=-4
(1/2;(√13-1)/2)
3-x-x^2>=2x-1
x^2+3x-4<=0
(-4;1)
[1/2;1]
(-1-√13)/2;1/2
3-x-x^2>=1-2x
x^2-x-2<=0
[-1;1/2]
(-∞;-4] U [-1;1] U [2;∞)