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shugi
@shugi
November 2021
2
14
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решение квадратных неравенств
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alinafrienddol
Решение в прикреплёнке
0 votes
Thanks 1
KarinaYouchi
Вы знак в 4-ом номере не поменяли, когда D искали
alinafrienddol
там 3 минуса, минус на минус и на минус будет минус, всё в порядке там
alinafrienddol
а не, не то увидела, вы правы)
KarinaYouchi
бывает)
KarinaYouchi
4.
8x^2+10x-3≥0
8x^2+10x-3=0
D=10^2-4*8*(-3)=100+96=196
x1=-10+√196=-10+14=4\16=1\4=0.25
2*8 16
x2=-10-√196=-10-14=-24=-6\4=-1.5
2*8 16 16
8x^2+10x-3=8(x-0.25)(x+1.5)
8(x-0.25)(x+1.5)≥0
+ - +
////////// //////////////////
---------[-1.5]-------------------------[0.25]----------------
Ответ:(-∞;-1.5]U[0.25;+∞)
6.
x^2+7x-60<0
x^2+7x-60=0
D=7^2-4*1*(-60)=49+240=289
x1=-7+√289=-7+17=10\2=5
2 2
x2=-7-√289=-7-17=-24\2=-12
2 2
x^2+7x-60=(x-5)(x+12)
(x-5)(x+12)<0
+ - +
/////////////////////////////////
----------(-12)---------------------------(5)-------------------
Ответ:(-12;5)
0 votes
Thanks 1
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Answers & Comments
8x^2+10x-3≥0
8x^2+10x-3=0
D=10^2-4*8*(-3)=100+96=196
x1=-10+√196=-10+14=4\16=1\4=0.25
2*8 16
x2=-10-√196=-10-14=-24=-6\4=-1.5
2*8 16 16
8x^2+10x-3=8(x-0.25)(x+1.5)
8(x-0.25)(x+1.5)≥0
+ - +
////////// //////////////////
---------[-1.5]-------------------------[0.25]----------------
Ответ:(-∞;-1.5]U[0.25;+∞)
6.
x^2+7x-60<0
x^2+7x-60=0
D=7^2-4*1*(-60)=49+240=289
x1=-7+√289=-7+17=10\2=5
2 2
x2=-7-√289=-7-17=-24\2=-12
2 2
x^2+7x-60=(x-5)(x+12)
(x-5)(x+12)<0
+ - +
/////////////////////////////////
----------(-12)---------------------------(5)-------------------
Ответ:(-12;5)