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dianakalashik
@dianakalashik
July 2022
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Реши квадратное уравнение 4x^ 2 −14x+6=0
Корни: x 1 = x 2 =
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oppression
4x²-14х+6=0,
2(2х²-х-6х+3)=0,
2(х(2х-1)-3(2х-1))=0,
2(х-3)(2х-1)=0,
(х-3)(2х-1)=0,
х-3=0, 2х-1=0,
х=3. 2х=1,
х=0,5.
Ответ: х₁=0,5; х₂=3.
11 votes
Thanks 11
germi0naa
4х²-14х+6=0
D=(-14)²-4•4•6=196-96=100
x1=-(-14)-√100/2•(-14)=14-10/-28=-4/28=-1/7
x2=-(-14)+√100/2•(-14)=14+10/-28=-24/28=-6/7
Ответ: х1=-1/7; х2=-6/7
6 votes
Thanks 1
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Answers & Comments
2(2х²-х-6х+3)=0,
2(х(2х-1)-3(2х-1))=0,
2(х-3)(2х-1)=0,
(х-3)(2х-1)=0,
х-3=0, 2х-1=0,
х=3. 2х=1,
х=0,5.
Ответ: х₁=0,5; х₂=3.
D=(-14)²-4•4•6=196-96=100
x1=-(-14)-√100/2•(-14)=14-10/-28=-4/28=-1/7
x2=-(-14)+√100/2•(-14)=14+10/-28=-24/28=-6/7
Ответ: х1=-1/7; х2=-6/7