Home
О нас
Products
Services
Регистрация
Войти
Поиск
КолосовНикита
@КолосовНикита
September 2021
1
10
Report
Реши систему неравенств.
x3<25x
6x2+53x>9
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
TARTILLO
Verified answer
Реши систему неравенств. - + - +
x^3<25x x(x
²-25)<0 ///////////////(-5)------0//////////////5]-----------
+ - +
6x^2+53x>9 6(x+9)(x-1/6)>0 ////////(-9)------------------(1/6)//////////////////
x
∈(-∞;-9)∪(1/6;5]
2 votes
Thanks 3
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Реши систему неравенств. x3<25x 6x2+53x>9..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Реши систему неравенств. - + - +x^3<25x x(x²-25)<0 ///////////////(-5)------0//////////////5]-----------
+ - +
6x^2+53x>9 6(x+9)(x-1/6)>0 ////////(-9)------------------(1/6)//////////////////
x∈(-∞;-9)∪(1/6;5]