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26Liza
@26Liza
July 2022
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Реши уравнение 121x+121−x^3−x^2=0
x1=
x2=
x3=
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Pacanka202
(121х–х^3)+(121–х^2)=0
х(121–х^2)+(121–х^2)=0
(121–х^2)(х+1)=0
121–х^2=0; х+1=0
(11–х)(11+х)=0; х=–1
11–х=0; 11+х=0
х=11; х=–11
Ответ: х1=11; х2=–11; х3=–1
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Answers & Comments
х(121–х^2)+(121–х^2)=0
(121–х^2)(х+1)=0
121–х^2=0; х+1=0
(11–х)(11+х)=0; х=–1
11–х=0; 11+х=0
х=11; х=–11
Ответ: х1=11; х2=–11; х3=–1