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Laingraim
@Laingraim
June 2022
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Реши уравнение:
2x(x+16)^2−x^2(x+16)=0
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gnomiha211
2x(x+16)^2−x^2(x+16)=0
2x(x^2+32x+256) - x^3- 16x^2=0
2x^3+ 64x^2+512x -x^3-16x^2=0
x^3 +48x^2+512x=0
x( x^2+48x+512)=0
x1=0 или x^2+48x+512=0
по теореме Виета
x2+x3=-48 x2= -32
x2*x3= 512 x3= -16
Ответ: У уравнения 3 корня:
x1= 0
x2= -32
x3= -16
2 votes
Thanks 5
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Answers & Comments
2x(x^2+32x+256) - x^3- 16x^2=0
2x^3+ 64x^2+512x -x^3-16x^2=0
x^3 +48x^2+512x=0
x( x^2+48x+512)=0
x1=0 или x^2+48x+512=0
по теореме Виета
x2+x3=-48 x2= -32
x2*x3= 512 x3= -16
Ответ: У уравнения 3 корня:
x1= 0
x2= -32
x3= -16