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petroffr
@petroffr
July 2022
2
5
Report
Реши уравнение:
2x(x−9)2−x2(x−9)=0
Ответ:
x1=x2=x3=
(Корни вводи в порядке возрастания их модулей)
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Universalka
Verified answer
2x(x - 9)² - x²(x - 9) = 0
(x - 9)[2x(x - 9) - x²] = 0
(x - 9)(2x² - 18x - x²) = 0
(x - 9)(x² - 18x) = 0
x(x - 9)(x - 18) = 0
или x₁ = 0 или x - 9 = 0 или x - 18 = 0
x₂ = 9 x₃ = 18
Отвеи : 0 ; 9 ; 18
2 votes
Thanks 7
2407Alexa
(x-9)(2x*(x-9)-x^2)=0
(x-9)=0
x=9
(2x*(x-9)-x^2)=0
2x^2-18x -x^2=0
x^2-18x=0
x*(x-18)=0
x=0
(x-18)=0
x=18
x1=0
x2=9
x3=18
1 votes
Thanks 1
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Answers & Comments
Verified answer
2x(x - 9)² - x²(x - 9) = 0(x - 9)[2x(x - 9) - x²] = 0
(x - 9)(2x² - 18x - x²) = 0
(x - 9)(x² - 18x) = 0
x(x - 9)(x - 18) = 0
или x₁ = 0 или x - 9 = 0 или x - 18 = 0
x₂ = 9 x₃ = 18
Отвеи : 0 ; 9 ; 18
(x-9)=0
x=9
(2x*(x-9)-x^2)=0
2x^2-18x -x^2=0
x^2-18x=0
x*(x-18)=0
x=0
(x-18)=0
x=18
x1=0
x2=9
x3=18