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katya11114
@katya11114
August 2022
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реши уравнение :а) 29*(145 - 6z )=203 б)(127-x) :4=24 в) 13a+14a-1609=1307
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vmaluga2011
А)
29(145-6z)=203
145-6z=203:29
145-6z=7
145-7=6z
6z=138
z=138:6
z=23
б)
(127-х):4=24
127-х=24*4
127-х=96
127-96=х
х=31
в)
13а+14а-1609=1307
27а=1307+1609
27а=2916
а=2916:27
а=108
2 votes
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Answers & Comments
29(145-6z)=203
145-6z=203:29
145-6z=7
145-7=6z
6z=138
z=138:6
z=23
б)
(127-х):4=24
127-х=24*4
127-х=96
127-96=х
х=31
в)
13а+14а-1609=1307
27а=1307+1609
27а=2916
а=2916:27
а=108