2x(x+4)²-x²(x+4)=0(x+4)(2x²+8x-x²)=0x(x+4)(x+8)=0x=0 x=-4 x=-8Ответ: 0, -4, -8
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2x(x+4)²-x²(x+4)=0
(x+4)(2x²+8x-x²)=0
x(x+4)(x+8)=0
x=0 x=-4 x=-8
Ответ: 0, -4, -8