Реши уравнения с двумя парами скобок. Выдели полученные корни.
2(3 + y) + 3(2y + 4) = 2
3(3u + 1) − 4(u − 4) = 29
7(2x + 3) = 91 − 4(3x − 2)
2(2v − 4) = 4(3 − v) − 44
5(3z − 2) = −16 − 3(2z + 5)
4(6y − 5) = 5(2y − 3) + 51
3(2x − 1) = 55 − 4(x + 2)
Варианты ответов:
–5
,
–4
,
–3
,
–2
,
–1
,
0
,
1
,
2
,
3
,
4
,
5
Answers & Comments
Ответ:
Пошаговое объяснение:
2(3 + y) + 3(2y + 4) = 2
6 + 2y + 6y + 12 = 2
18 + 8y = 2
8y = 2 - 18
8y = -16
y = -16 : 8
y = -2
3(3u + 1) − 4(u − 4) = 29
9u + 3 - 4u + 16 = 29
5u + 19 = 29
5u = 29-19
5u = 10
u = 10:5
u = 2
7(2x + 3) = 91 − 4(3x − 2)
14x + 21 = 91 - 12x + 8
14x + 21 = 99 - 12x
14x + 12x = 99 - 21
26x = 78
x = 78:26
x = 2
2(2v − 4) = 4(3 − v) − 44
4v - 8 = 12 - 4v - 44
4v - 8 = -32 - 4v
4v + 4v = -32 + 8
8v = -24
v = -24:8
v = -3
5(3z − 2) = −16 − 3(2z + 5)
15z - 10 = -16 - 6z - 15
15z - 10 = -31 - 6z
15z + 6z = -31 + 10
21z = -21
z = -21:21
z = -1
4(6y − 5) = 5(2y − 3) + 51
24y - 20 = 10y - 15 + 51
24y - 20 = 10y + 36
24y - 10y = 36 + 20
14y = 56
y = 56:14
y = 4
3(2x − 1) = 55 − 4(x + 2)
6x - 3 = 55 - 4x - 8
6x - 3 = 47 - 4x
6x + 4x = 47 + 3
10x = 50
x = 50:10
x = 5