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5natusik5
@5natusik5
August 2022
2
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Решить
2-6sinxcosx=0
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dtnth
Verified answer
Используя формулу синуса двойного угла
перепишем уравнение
k є Z
5 votes
Thanks 6
ЕкарныйБабай
Sin2x=2sinx cosx
2-6sinxcosx=0
2-3sin 2x=0
sin2x= 2/3
2x= (-1)^k arcsin(2/3) +
πk k⊂Z
x= (-1)^k arcsin(2/3) / 2+ πk/2 k⊂Z
2 votes
Thanks 2
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Answers & Comments
Verified answer
Используя формулу синуса двойного углаперепишем уравнение
k є Z
2-6sinxcosx=0
2-3sin 2x=0
sin2x= 2/3
2x= (-1)^k arcsin(2/3) + πk k⊂Z
x= (-1)^k arcsin(2/3) / 2+ πk/2 k⊂Z