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doc2134
@doc2134
July 2022
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Решить 2 уравнения. Пожалуйста, как можно быстрее)
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TARTILLO
Verified answer
Решить уравнения.
1) (2x
²+x-1)/(x²-1)=0
(2x²+x-1)/(x²-1)=0 ⇔ (2x
²+x-1)=0
D=1+8=9
x1=(-1-3)/4=-1 x2=(-1+3)/4=1/2
одз: x≠
1, x≠-1 , т.о. x=1/2
проверка:
(2(1/2)²+(1/2)-1)/((1/2)²-1)= (2(1/4)+(1/2)-1)/((1/4)
-1)=
= (1/2+1/2-1)/(-3/4) =0/(-3/4
) =0
ответ: x=1/2
2) (2x²-5x-3)/(x²-9)=0
((2x
²-5x-3)/(x²-9)=0
⇔ (2x
²-5x-3)=0
D=25+24=49
x1=(5-7)/4=-1/2 x2=
(5+7)/4=3
одз: x≠
3, x≠-3 , т.о. x=-1/2
проверка:
(2(-1/2)²-5(-1/2)-3)/((-1/2)²-9)= (2(1/4)+(5/2)-3)/((1/4)
-9)=
= (1/2+5/2-3)/(-35/4) =0/(-35/4
) =0
ответ: x=-1/2
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Answers & Comments
Verified answer
Решить уравнения.1) (2x²+x-1)/(x²-1)=0
(2x²+x-1)/(x²-1)=0 ⇔ (2x²+x-1)=0
D=1+8=9 x1=(-1-3)/4=-1 x2=(-1+3)/4=1/2
одз: x≠1, x≠-1 , т.о. x=1/2
проверка:
(2(1/2)²+(1/2)-1)/((1/2)²-1)= (2(1/4)+(1/2)-1)/((1/4)-1)=
= (1/2+1/2-1)/(-3/4) =0/(-3/4) =0
ответ: x=1/2
2) (2x²-5x-3)/(x²-9)=0
((2x²-5x-3)/(x²-9)=0 ⇔ (2x²-5x-3)=0
D=25+24=49 x1=(5-7)/4=-1/2 x2=(5+7)/4=3
одз: x≠3, x≠-3 , т.о. x=-1/2
проверка:
(2(-1/2)²-5(-1/2)-3)/((-1/2)²-9)= (2(1/4)+(5/2)-3)/((1/4)-9)=
= (1/2+5/2-3)/(-35/4) =0/(-35/4) =0
ответ: x=-1/2