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dendedendep0fm72
@dendedendep0fm72
July 2022
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Решить 5 и 6 номер (подробно)
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tseluykoln
5. SC=h/sinβ из ΔСOS
S(BSC)=1/2*h²/sin²β *sinα=h²sinα/2sin²β
6. AC=m/cosα из ΔACD
ΔASC, ∠A=90°-α, ∠S=2α
S(ASC)=1/2 * m²/cos²α *sin2α=m²sin2α/(2cos²α)
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Answers & Comments
S(BSC)=1/2*h²/sin²β *sinα=h²sinα/2sin²β
6. AC=m/cosα из ΔACD
ΔASC, ∠A=90°-α, ∠S=2α
S(ASC)=1/2 * m²/cos²α *sin2α=m²sin2α/(2cos²α)