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waynerooney19
@waynerooney19
June 2022
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Решить квадратное уравнение:
4(x-2)^2=12x+3
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Nailyamk
4x^-4*4=12x+3
4x^-16-12x-3=0
4x^-12x-13=0
По моему так)
1 votes
Thanks 0
Nyanny
4(x-2)^2=12x+3
4(x^2-4x+4)=12x+3
4x^2-28x+13=0
D=b^2-4ac
D=576=24^2
x1,2=-b+-корень из D/2a
x1=28+24/8=6,5
x2=28-24/8=0,5
1 votes
Thanks 0
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Answers & Comments
4x^-16-12x-3=0
4x^-12x-13=0
По моему так)
4(x^2-4x+4)=12x+3
4x^2-28x+13=0
D=b^2-4ac
D=576=24^2
x1,2=-b+-корень из D/2a
x1=28+24/8=6,5
x2=28-24/8=0,5