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epitos
@epitos
March 2022
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решить линейные неравенства.
2a-4>a+3
3x+2<-2x+1
2(1-x)-4(2x-3) больше меньше (или равно) 1
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iїi
1) 2a-4>a+3
-4-3>а-2а
-7>-а
а>7
а(7;+бесконечность)
2) 3x+2<-2x+1
3х+2х<1-2
5х<-1
х<-0,5
х(-бесконечность; - 0,5)
3) 2(1-x)-4(2x-3)><= 1
2-2х-8х+12><=1
-2х-8х><=1-2-12
-10х><=-13
х<>=1,3
х [1,3]
1 votes
Thanks 1
epitos
спасибо огромное
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Answers & Comments
-4-3>а-2а
-7>-а
а>7
а(7;+бесконечность)
2) 3x+2<-2x+1
3х+2х<1-2
5х<-1
х<-0,5
х(-бесконечность; - 0,5)
3) 2(1-x)-4(2x-3)><= 1
2-2х-8х+12><=1
-2х-8х><=1-2-12
-10х><=-13
х<>=1,3
х [1,3]