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krista20001
@krista20001
August 2022
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Решить методом выделения полного квадрата х^2-8х-у+12=0
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erzhan9210
X²-8x-y+12=0
y=x²-8x+12 = (x²-8x+16)-16+12 = (x-4)²-4
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Answers & Comments
y=x²-8x+12 = (x²-8x+16)-16+12 = (x-4)²-4