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naska98
@naska98
August 2022
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решить неравенство 2cosx^2+3cosx+1больше0
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mikael2
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Cosx=z 2z²+3z+1=0 D=9-8=1 √1=1 z1=1/4[-3-1]=-1 z2=1/4[-3+1]=-1/2
-------------- -1--------------------- -1/2--------------
+ - +
cosx<-1 нет решения поскольку -1 не входит.
соsx >-1/2 -2/3π+2πk<x<2/3π+2πk k∈Z
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Answers & Comments
Verified answer
Cosx=z 2z²+3z+1=0 D=9-8=1 √1=1 z1=1/4[-3-1]=-1 z2=1/4[-3+1]=-1/2-------------- -1--------------------- -1/2--------------
+ - +
cosx<-1 нет решения поскольку -1 не входит.
соsx >-1/2 -2/3π+2πk<x<2/3π+2πk k∈Z