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August 2022
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Решить неравенство (2x^2+11x+6)(2x^2+11x+13)>8
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oganesbagoyan
Verified answer
Решить неравенство (2x^2+11x+6)(2x^2+11x+13)>8
-----------------------------------
(2x² +11x +6)(2
x² +11x +13) >8 ;
обозначаем t =2x² +11x +6
;
t(t+7) > 8;
t
² +7t -8>0;
t
² -t +8t -8>0;
t(t-1) +8(t-1) >0;
(t+8)(t-1) >0 .
t
∈( -
∞; - 8) U
(1;∞).
а)
2x² +11x +6 < -8 ;
2x² +11x +14<0 ;
2(x +7/2)(x+2) < 0;
x∈( -7/2 ; -2) .
-----------------
б)
2
x² +11x +6
> 1
;
2x² +11x +5 > 0
;
x
² +(5+1/2)x + 5*1/2 > 0;
2(x+5)(x+1/2) >0 ;
x∈(-∞; - 5) U (-1/2 ;∞)
объединяя
( -7/2 ; -2) и
(-∞; - 5) U (-1/2 ;∞) ,
получим :
ответ :x∈
(-∞; - 5) U (
-7/2 ; -2) U
(-1/2 ;∞)
.
1 votes
Thanks 2
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Verified answer
Решить неравенство (2x^2+11x+6)(2x^2+11x+13)>8-----------------------------------
(2x² +11x +6)(2x² +11x +13) >8 ;
обозначаем t =2x² +11x +6 ;
t(t+7) > 8;
t² +7t -8>0;
t² -t +8t -8>0;
t(t-1) +8(t-1) >0;
(t+8)(t-1) >0 .
t ∈( -∞; - 8) U (1;∞).
а) 2x² +11x +6 < -8 ;
2x² +11x +14<0 ;
2(x +7/2)(x+2) < 0;
x∈( -7/2 ; -2) .
-----------------
б) 2x² +11x +6> 1 ;
2x² +11x +5 > 0 ;
x² +(5+1/2)x + 5*1/2 > 0;
2(x+5)(x+1/2) >0 ;
x∈(-∞; - 5) U (-1/2 ;∞) объединяя ( -7/2 ; -2) и (-∞; - 5) U (-1/2 ;∞) , получим :
ответ :x∈ (-∞; - 5) U ( -7/2 ; -2) U (-1/2 ;∞).