Решить неравенство а) ( 2x - 3 ) (x+4) > 0 б) x² -16 < 0. Created by adelya606. algebra-ru

Решить неравенство а) ( 2x - 3 ) (x+4) > 0 б) x² -16

August 2022 1 11 Report

Решить неравенство

а) ( 2x - 3 ) (x+4) > 0
б) x² -16 < 0

Answers & Comments

marinin2003 1)
2х^2+8х-3х-12>0
2х^2+5х-12
D= 25 -4 × 2 × (-12) = 25 + 96 = 121 = 11^2
х1 = (-5 + 11)/4 = 1 1/2
х2 = (-5 - 11)/4 = -4
х1 > 0. Ответ 1 1/2

2) х^2 = 16
х1,2 = +-4
х2 < 0. Ответ -4

2 votes Thanks 1

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adelya606 August 2022 | 0 Ответы

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