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steparomashkin
@steparomashkin
August 2022
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Решить неравенство: f'(x)<0, если f(x)=x^3-23x+26
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Utem
F'(x)=(x³-23x+26)'=3x²-23
3x²-23<0
3x²<23
x²<23/3
x<√(23/3) x>-√(23/3)
x∈(-√(23/3);√(23/3))
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Answers & Comments
3x²-23<0
3x²<23
x²<23/3
x<√(23/3) x>-√(23/3)
x∈(-√(23/3);√(23/3))