решить неравенство
х^2-8х+7 меньше равно 0
[1;7]
D=64-4*7=36
x=(8+6)/2=7
x=(8-6)/2=1
(x-7)(x-1)<=0
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[1;7]
Verified answer
D=64-4*7=36
x=(8+6)/2=7
x=(8-6)/2=1
(x-7)(x-1)<=0