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JuliKami
@JuliKami
October 2021
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решить неравенство: log_3(x^2+5)>log_3(x+7)
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yellok
3>1 ⇒ x²+5>x+7
x²-x-2>0
D=1+2*4=9
x₁=(1+3)/2=2
x₂=(1-3)/2=-1
x²-x-2>0
⇒ (x+1)(x-2)>0 ⇒ x∈(-∞, -1)∨(2,+∞)
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Answers & Comments
3>1 ⇒ x²+5>x+7
x²-x-2>0
D=1+2*4=9
x₁=(1+3)/2=2
x₂=(1-3)/2=-1
x²-x-2>0 ⇒ (x+1)(x-2)>0 ⇒ x∈(-∞, -1)∨(2,+∞)