sedinalana

Verified answer

ОДЗ
25-x²>0
x∈(-5;5)
log(3)(25-x²)=t
t²-3t+2≥0
t1+t2=3 U t1*t2=2
t1=1 U t2=2
t≤1⇒log(3)(25-x²)≤1
25-x²≤3⇒22-x²≤0⇒x≤-√22 U x≥√22
t≥2⇒log(3)(25-x²)≥2
25-x²≥9⇒16-x²≥0⇒-4≤x≤4
Ответ x∈(-5;-√22] U  U [-4;4] U [22;5)