решить неравенство с ответом. Created by anutaerm. algebra-ru

решить неравенство с ответом...

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$\left \{ {{ \frac{9}{x^2 } \geq 1 \atop { \frac{1}{x+2} \geq 0 } \right.=\ \textgreater \ \left \{ {{ \frac{9}{x^2}-1 \geq 0 } \atop { \frac{1}{x+2} \geq 0 }} \right.=\ \textgreater \ \left \{ {{ \frac{9-x^2}{x^2} \geq 0 } \atop { \frac{1}{x+2} \geq 0 }} \right.=\ \textgreater \ \left \{ {{ \frac{(3-x)(3+x)}{x^2} \geq 0 } \atop { \frac{1}{x+2} \geq 0 }} \right.$

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x∈(2;0)U(0;3] и x∈Z (по условию)
x={-1;1;2;3}
Находим произведение целых значений, входящих в неравенство:
-1*1*2*3=6
Ответ: 6

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