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natali200117
@natali200117
September 2021
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Решить неравенство:3^2х-12*3х+27 меньше равно 0
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PolinkaKro
Положим 3^x=t, t>0
t^2-12t+27=0
D=(-12)^2-4*27=144-108=36
t1= 12-6/2=3 t2=12+6/2=9
3^x=3 3^x=9
3^x=3^1 3^x=3^2
x=1 x=2
ответ 1;2
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Answers & Comments
t^2-12t+27=0
D=(-12)^2-4*27=144-108=36
t1= 12-6/2=3 t2=12+6/2=9
3^x=3 3^x=9
3^x=3^1 3^x=3^2
x=1 x=2
ответ 1;2