Решение1) limx-->0 [(√(7 - x) - √(7 + x))*(√(7 - x) + √(7 + x))] / (√7 *x) == lim x-->0 [(√(7 - x)² - (√(7 + x))²] / (√7 * x) = limx-->0 (7 - x - 7 - x) /(√7 * x) = lim x-->0 (- 2x) / (√7 * x) = = -2 / √7 = - 2√7 / 72) lim x-->-1 [(√5+ x) - 2)*(√(5 + x) + 2)*√(8 - x) + 3)] / /[(√(8 - x) - 3)*(√(8 - x) + 3)*(√(5 + x) + 2)] = lim x-->-1 [(5 + x - 4)** √(8- x) + 3)] / [(8 - x - 9) * (√(5 + x) + 2)] = lim x-->-1 [(1 + x)*(√(8 - x) + 3)] / [(11 -x)*(√(5 + x) + 2)] = 03) lim x-->4 [(2 - √x)*(2 + √x)*(√(6x + 1) + 5) ] / [(6x+ 1) - 5)* * (√(6x + 1) + 5)* (2 + √x)] = lim x-->4 [(4 - x)*(√(6x + 1) +5) ] // [(6x + 1 - 25)* (2 + √x)] = lim x-->4 [(4 - x)*(√(6x + 1) +5)] // [6*(x - 4)* (2 + √x) = - lim x-->4 [(4 - x)*(√(6x + 1) + 5)] / [6*(4 - x)* (2 + √x)] = - lim x-->4 [(√(6x + 1) + 5)] / [6* (2 + √x)] = 10/24 == 5 /124) lim x--> -1 [√(x + 20) - 4)*(√(x + 20) + 4)] / (x³+ 64) = lim x--> - 1 (x + 20 - 16) / (x³+ 64) = lim x--> - 1 (x + 4) / [(x+ 4)*(x² - 4x + 16)] = lim x--> -1 [1 / (x² - 4x + 16)] = 1/215) lim x--> 3 (2x³- 3x - 9) / [(√x - 2) - √(4 - x)] = 2x² - 3x - 9 = 0D = 9 + 4*2*9 = 81x = (3 - 9)/4 = - 3/2x = (3 + 9)/4 = 3 lim x--> 3 [2*(x + 1,5)*(x - 3)*(√(x - 2) + √(4 - x)] / / [(√(x - 2) - √(4 - x)) * (√(x - 2) + √(4 - x))] = lim x--> 3 [2*(x + 1,5)*(x - 3)*(√(x - 2) + √(4 - x))] / (x - 2 - 4 + x) == lim x--> 3 [2*(x + 1,5)*(x - 3)*(√(x - 2) + √(4 - x))] / [2*(x - 3)] == lim x--> 3 [2*(x + 1,5)*(√(x - 2) + √(4 - x))] / 2 == (2*4,5*2) / 2 = 9
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Решение
1) limx-->0 [(√(7 - x) - √(7 + x))*(√(7 - x) + √(7 + x))] / (√7 *x) =
= lim x-->0 [(√(7 - x)² - (√(7 + x))²] / (√7 * x) =
limx-->0 (7 - x - 7 - x) /(√7 * x) = lim x-->0 (- 2x) / (√7 * x) =
= -2 / √7 = - 2√7 / 7
2) lim x-->-1 [(√5+ x) - 2)*(√(5 + x) + 2)*√(8 - x) + 3)] /
/[(√(8 - x) - 3)*(√(8 - x) + 3)*(√(5 + x) + 2)] = lim x-->-1 [(5 + x - 4)*
* √(8- x) + 3)] / [(8 - x - 9) * (√(5 + x) + 2)]
= lim x-->-1 [(1 + x)*(√(8 - x) + 3)] / [(11 -x)*(√(5 + x) + 2)] = 0
3) lim x-->4 [(2 - √x)*(2 + √x)*(√(6x + 1) + 5) ] / [(6x+ 1) - 5)*
* (√(6x + 1) + 5)* (2 + √x)] = lim x-->4 [(4 - x)*(√(6x + 1) +5) ] /
/ [(6x + 1 - 25)* (2 + √x)] = lim x-->4 [(4 - x)*(√(6x + 1) +5)] /
/ [6*(x - 4)* (2 + √x) = - lim x-->4 [(4 - x)*(√(6x + 1) + 5)] /
[6*(4 - x)* (2 + √x)] = - lim x-->4 [(√(6x + 1) + 5)] / [6* (2 + √x)] = 10/24 =
= 5 /12
4) lim x--> -1 [√(x + 20) - 4)*(√(x + 20) + 4)] / (x³+ 64) =
lim x--> - 1 (x + 20 - 16) / (x³+ 64) = lim x--> - 1 (x + 4) / [(x+ 4)*(x² - 4x + 16)] = lim x--> -1 [1 / (x² - 4x + 16)] = 1/21
5) lim x--> 3 (2x³- 3x - 9) / [(√x - 2) - √(4 - x)] =
2x² - 3x - 9 = 0
D = 9 + 4*2*9 = 81
x = (3 - 9)/4 = - 3/2
x = (3 + 9)/4 = 3
lim x--> 3 [2*(x + 1,5)*(x - 3)*(√(x - 2) + √(4 - x)] /
/ [(√(x - 2) - √(4 - x)) * (√(x - 2) + √(4 - x))] =
lim x--> 3 [2*(x + 1,5)*(x - 3)*(√(x - 2) + √(4 - x))] / (x - 2 - 4 + x) =
= lim x--> 3 [2*(x + 1,5)*(x - 3)*(√(x - 2) + √(4 - x))] / [2*(x - 3)] =
= lim x--> 3 [2*(x + 1,5)*(√(x - 2) + √(4 - x))] / 2 =
= (2*4,5*2) / 2 = 9