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tanyatimchenko
@tanyatimchenko
July 2021
1
10
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Решить рациональное уравнение
Пожалуйста под 6
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m11m
1-х
-
2х
=
4
х-3 3х+2 6+7х-3х²
1-х
-
2х
-
4
=0
х-3 3х+2 6+7х-3х²
Разложим 6+7х-3х² на множители:
6+7х-3х² =0
3х²-7х-6=0
D=(-7)² - 4*3*(-6)=49+72=121
x₁=
7- 11
= -4/6 = -2/3
6
x₂=
7+11
=3
6
6+7x-3x² = -3(x+²/₃)(x-3)= - (3x+2)(x-3)
1-x
-
2x
-
4
=0
x-3 3x+2 -(3x+2)(x-3)
1-x
-
2x
+
4
=0
x-3 3x+2 (3x+2)(x-3)
ОДЗ: х≠3 х≠ -2/3
(1-х)(3х+2)-2х(х-3)+4=0
3х-3х²+2-2х-2х²+6х+4=0
-5х²+7х+6=0
5х²-7х-6=0
D=(-7)² - 4*5*(-6)=49+120=169
x₁=
7-13
= -0.6
10
x₂ =
7+13
= 2
10
Ответ: -0,6; 2.
0 votes
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Answers & Comments
х-3 3х+2 6+7х-3х²
1-х - 2х - 4 =0
х-3 3х+2 6+7х-3х²
Разложим 6+7х-3х² на множители:
6+7х-3х² =0
3х²-7х-6=0
D=(-7)² - 4*3*(-6)=49+72=121
x₁= 7- 11 = -4/6 = -2/3
6
x₂= 7+11 =3
6
6+7x-3x² = -3(x+²/₃)(x-3)= - (3x+2)(x-3)
1-x - 2x - 4 =0
x-3 3x+2 -(3x+2)(x-3)
1-x - 2x + 4 =0
x-3 3x+2 (3x+2)(x-3)
ОДЗ: х≠3 х≠ -2/3
(1-х)(3х+2)-2х(х-3)+4=0
3х-3х²+2-2х-2х²+6х+4=0
-5х²+7х+6=0
5х²-7х-6=0
D=(-7)² - 4*5*(-6)=49+120=169
x₁= 7-13 = -0.6
10
x₂ = 7+13 = 2
10
Ответ: -0,6; 2.