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Mrgray
@Mrgray
July 2022
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Решить систему.
2^y*3^x=72
3^y*2^x=108
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dnepr1
Verified answer
2^y*3^x=72 = 2³*3²
3^y*2^x=108 =3
³*2²
72 =
1 · 2
³
· 3
²,
108
=
1 · 2
²
· 3
³.
Отсюда видим, что х = 2, у = 3.
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Answers & Comments
Verified answer
2^y*3^x=72 = 2³*3²3^y*2^x=108 =3³*2²
72 = 1 · 2³ · 3²,
108 = 1 · 2² · 3³.
Отсюда видим, что х = 2, у = 3.