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dkirina
@dkirina
July 2022
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Решить систему:
{8х+2у=11
{6х-4у=11
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OxikoOne
[tex] \left \{ {{8x+2y=11} \atop {6x-4y=11}} \right. \left \{ {{2y=11-8x } \atop {6x-4y=11}} \right. \left \{ {{y=5.5-4x} \atop {6x-4y=11}} \right. [/tex]6х-4(5.5-4x)=116х- 22+16х=1122х=11+22=33х=1.5___при х=1.5у=5.5-4×1.5 = 5.5- 6 = -0.5
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Thanks 2
dkirina
а от куда 5,5 и 4x ?
OxikoOne
Уравнение 2у=11-8х поделили на 2
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