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МаргоРитка16
@МаргоРитка16
July 2022
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решить систему:
-х квадрат +2х+4=у
у+3х=8
и сказать каким способом решали
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Удачник66
Verified answer
Подстановкой
-x^2 + 2x + 4 = y
y = 8 - 3x
-x^2 + 2x + 4 = 8 - 3x
-x^2 + 2x + 4 - 8 + 3x = 0
-x^2 + 5x - 4 = 0
x^2 - 5x + 4 = 0
(x - 1)(x - 4) = 0
x1 = 1, y1 = 8 - 3 = 5
x2 = 4, y2 = 8 - 12 = -4
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Answers & Comments
Verified answer
Подстановкой-x^2 + 2x + 4 = y
y = 8 - 3x
-x^2 + 2x + 4 = 8 - 3x
-x^2 + 2x + 4 - 8 + 3x = 0
-x^2 + 5x - 4 = 0
x^2 - 5x + 4 = 0
(x - 1)(x - 4) = 0
x1 = 1, y1 = 8 - 3 = 5
x2 = 4, y2 = 8 - 12 = -4