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gorbuldanila
@gorbuldanila
July 2022
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Решить систему уравнений
x²+y²-10=0
xy-3=0
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Виктория0503
Verified answer
X²+y²-10=0
xy-3=0
1) xy-3=0
ху=3
х=3/у
2) (3/у)²+у²-10=0
9/у²+у²-10=0 (*у²)
9+2у²-10у²=0
9-8у²=0
-8у²=-9
у²=9/8
у1=3/(2√2)
у2=-3/(2√2)
3) х1 = 3 : 3/(2√2) = (2√2)
х2 = 3 : (-3/(2√2)) = - (2√2)
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gorbuldanila
ответ в книге такой:
gorbuldanila
(-3;-
gorbuldanila
(-3;-1) (3;1) (-1;-3) (1;3)
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Answers & Comments
Verified answer
X²+y²-10=0xy-3=0
1) xy-3=0
ху=3
х=3/у
2) (3/у)²+у²-10=0
9/у²+у²-10=0 (*у²)
9+2у²-10у²=0
9-8у²=0
-8у²=-9
у²=9/8
у1=3/(2√2)
у2=-3/(2√2)
3) х1 = 3 : 3/(2√2) = (2√2)
х2 = 3 : (-3/(2√2)) = - (2√2)