║ 3(х+у) - ху = -1,
║ 4ху + х + у = -9,
║ (х + у)+ 4ху = -9, (*-3),
║ -3(х + у) - 12ху = 27,
3(х+у) - ху - 3(х + у) - 12ху = -1 + 27,
-13ху = 26,
ху = -2,
х = -2/у,
подставим в 1 ур-ие:
3(-2/у + у) - (-2) = -1,
-6/у + 3у + 2 = -1,
-6 + 3у² + 2у = -у,
3у² + 3у - 6 = 0,
у² + у - 2 = 0,
Д = 1² - 4*1*(-2) = 1 + 8 = 9,
у1 = (-1+3) / 2*1 = 2/2 = 1,
у2 = (-1-3) / 2*1 = -4/2 = -2,
х1 = -2 / у1 = -2 / 1 = -2,
х2 = -2 / у2 = -2 / (-2) = 1,
ответ: (-2; 1), (1; -2)
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
║ 3(х+у) - ху = -1,
║ 4ху + х + у = -9,
║ 3(х+у) - ху = -1,
║ (х + у)+ 4ху = -9, (*-3),
║ 3(х+у) - ху = -1,
║ -3(х + у) - 12ху = 27,
3(х+у) - ху - 3(х + у) - 12ху = -1 + 27,
-13ху = 26,
ху = -2,
х = -2/у,
подставим в 1 ур-ие:
3(-2/у + у) - (-2) = -1,
-6/у + 3у + 2 = -1,
-6 + 3у² + 2у = -у,
3у² + 3у - 6 = 0,
у² + у - 2 = 0,
Д = 1² - 4*1*(-2) = 1 + 8 = 9,
у1 = (-1+3) / 2*1 = 2/2 = 1,
у2 = (-1-3) / 2*1 = -4/2 = -2,
х1 = -2 / у1 = -2 / 1 = -2,
х2 = -2 / у2 = -2 / (-2) = 1,
ответ: (-2; 1), (1; -2)