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katiavasilevaaw
@katiavasilevaaw
August 2021
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Решить способом группировки:
1) y^3-4+2y-2y^2
2)z-3z^2+z^3-3
3)x^3+28-14x^2-2x
4)2b^3-6-4b^2+3b
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ВикаВикторовна
Verified answer
1) =(y³-2y²)+(2y-4)=y²(y-2)+2(y-2)=(y-2)(y²+2)
2) =(z-3)+(z³-3z²)=(z-3)+z²(z-3)=(z-3)(1+z²)
3) =(x³-14x²)-(2x-28)=x²(x-14)-2(x-14)=(x-14)(x²-2)
4) =(2b³-4b²)+(3b-6)=2b²(b-2)+3(b-2)=(b-2)(2b²+3)
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katiavasilevaaw
Реши еще это плз ,тоже самое,разложить на множители :1)18a^2+27ab+14ac+21bc 2)2x^2yz-15yz-3xz^2+10xy^2
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Answers & Comments
Verified answer
1) =(y³-2y²)+(2y-4)=y²(y-2)+2(y-2)=(y-2)(y²+2)2) =(z-3)+(z³-3z²)=(z-3)+z²(z-3)=(z-3)(1+z²)
3) =(x³-14x²)-(2x-28)=x²(x-14)-2(x-14)=(x-14)(x²-2)
4) =(2b³-4b²)+(3b-6)=2b²(b-2)+3(b-2)=(b-2)(2b²+3)