xy - 2x + 2x + 2y = yx + 2y;
xy - yx + 2y - 2y = 0;
0 = 0, доказано
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xy - 2x + 2x + 2y = yx + 2y;
xy - yx + 2y - 2y = 0;
0 = 0, доказано
x(y-2)+2(x+y)=xy-2x+2x+2y=xy+2y=
=y(x+2)