Решить уравнение 1) (2x + 3)² - 4(x - 1)(x+1)= 49;
2) (3x +4)² -(3x - 1)(1+3x) = 49;
3) x³ + 2x² - 9x -18 = 0;
4) y³ – 3y² - 4y +12 = 0.
2) (3x +4)² -(3x - 1)(1+3x) = 49;
3) x³ + 2x² - 9x -18 = 0;
4) y³ – 3y² - 4y +12 = 0.
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