Решить уравнение
1) (х+3)(х-2)-(х+4)(х+1)=38
2) 2х(3х-2,7)-12(2,7-3х)=0
3) (x+7)(x-2)- (x+4)(x+3)=-2
1) (х+3)(х-2)-(х+4)(х+1)=38
2) 2х(3х-2,7)-12(2,7-3х)=0
3) (x+7)(x-2)- (x+4)(x+3)=-2
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Answers & Comments
1) x-6-5x-1=38
-4x=45
x=-11,25
2) 6x^2-5,4x-32,4+36x=0
x^2-0,9x-5,4+6x=0
x^2+5,1x-5,4=0
D=5,1^2+4*5,4=47,61=6,9^2
x1=0,9
x2=-6
3) 5x-14-7x-12=2
-2x=28
x=14