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piepier1
@piepier1
July 2022
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РЕШИТЬ УРАВНЕНИЕ 2sinx+sin^2x+cos^2x=1
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hovsep50
2sinx + (sin²x+cos²x) =1
2sinx +1 = 1
sinx=0
x=πk ; k∈Z
4 votes
Thanks 6
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Answers & Comments
2sinx +1 = 1
sinx=0
x=πk ; k∈Z