Решить уравнение 2x в квадрате -12x-1=2(1-2x)
2x в квадрате -12x-1=2(1-2x)
2x^2-12x-1-2+4x=0
2x2 - 8x - 3 = 0D = b2 - 4acD = 64 + 24 = 88 = (2√22)^2
x1,2 = -b ± √D/2ax1 = 8 + 2√22/4 = 4 + √22//2x2 = 8 - 2√22/4 = 4 - √22/2Ответ: x1 = 4 + √22/2 ; x2 = 4 - √22/2
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2x в квадрате -12x-1=2(1-2x)
2x^2-12x-1-2+4x=0
2x2 - 8x - 3 = 0
D = b2 - 4ac
D = 64 + 24 = 88 = (2√22)^2
x1,2 = -b ± √D/2a
x1 = 8 + 2√22/4 = 4 + √22//2
x2 = 8 - 2√22/4 = 4 - √22/2
Ответ: x1 = 4 + √22/2
; x2 = 4 - √22/2