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esmiralda
@esmiralda
July 2022
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Решить уравнение 2x (в квадрате) = x+3
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СерыйВорон
2х^2-х-3=0
дискриминант 1+24=25
х1,2=(1+(-)√25)/4
х1=1.5
х2=-1
1 votes
Thanks 0
dg12025112000
2x^2=x+32x^2-x-3=0D=(-1)^2-4*2*(-3)=1+24=25X1=3+5 8 --- = --- = 2 2*2 4X2=3-5 -2 --- = --- = -0,5 2*2 4
Ответ: x1 = 2 x2 = -0,5
0 votes
Thanks 1
dg12025112000
2x^2=x+3
2x^2-x-3=0
D=(-1)^2-4*2*(-3)=1+24=25
X1=1+5 6
--- = --- = 1,5
2*2 4
X2=1-5 -4
--- = --- = -1
2*2 4
Ответ: x1 = 1,5
x2 = -1
dg12025112000
Это правильное решение уравнения
esmiralda
Спасибо!
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Answers & Comments
дискриминант 1+24=25
х1,2=(1+(-)√25)/4
х1=1.5
х2=-1
Ответ: x1 = 2 x2 = -0,5
2x^2-x-3=0
D=(-1)^2-4*2*(-3)=1+24=25
X1=1+5 6
--- = --- = 1,5
2*2 4
X2=1-5 -4
--- = --- = -1
2*2 4
Ответ: x1 = 1,5
x2 = -1