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VitALIk3101
@VitALIk3101
August 2022
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Решить уравнение -
(2x+3)(x-4)=0
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qwasd228
На картинке всё написано
2 votes
Thanks 0
VitALIk3101
Спасибо, но мне надо с решением
89210749631
2x²-8x+3x-12=0
2x²-5x-12=0
ax²+bx+c=0
D=b²-4ac
D=(-5)²-4*2*(-12)=11²
x1=4 x2= -1,5
2 votes
Thanks 1
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Answers & Comments
2x²-5x-12=0
ax²+bx+c=0
D=b²-4ac
D=(-5)²-4*2*(-12)=11²
x1=4 x2= -1,5